JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
Let \(H\) be the hyperbola, whose foci are \((1 \pm \sqrt{2}, 0)\) and eccentricity is \(\sqrt{2}\). Then the length of its latus rectum is
- A \(2\)
- B \(3\)
- C \(\frac{5}{2}\)
- D \(\frac{3}{2}\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
\(2 ae =|(1+\sqrt{2})-(1+\sqrt{2})|=2 \sqrt{2}\) \(ae =\sqrt{2}\) \(a =1\) \(\Rightarrow b =1 \quad \because e =\sqrt{2} \Rightarrow \text { Hyperbola is rectangular }\) \(\Rightarrow \text { L.R }=\frac{2 b ^2}{ a }=2\)
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