ExamBro
ExamBro
JEE Mains · Maths · STD 11 - 6. permutation and combination

The number of ordered pairs ( \(\mathrm{r}, \mathrm{k}\) ) for which \(6 \cdot ^{35} \mathrm{C}_{\mathrm{r}}=\left(\mathrm{k}^{2}-3\right)\cdot{^{36} \mathrm{C}_{\mathrm{r}+1}}\). where \(\mathrm{k}\) is an integer, is

  1. A \(3\)
  2. B \(2\)
  3. C \(4\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(4\)

Step-by-step Solution

Detailed explanation

\(6 \times^{35} \mathrm{C}_{\mathrm{r}}=\left(\mathrm{k}^{2}-3\right)^{36} \mathrm{C}_{\mathrm{r}+1}\) \(k^{2}-3>0 \Rightarrow k^{2}>3\) \(\mathrm{k}^{2}-3=\frac{6 \mathrm{\times}^{35} \mathrm{C}_{\mathrm{r}}}{^{36} \mathrm{C}_{\mathrm{r}+1}}=\frac{\mathrm{r}+1}{6}\) Possible…