JEE Mains · Maths · STD 12 - 10. vector algebra
The distance of the point having position vector \( - \,\hat i\, + \,2\hat j\, + 6\hat k\) from the straight line passing through the point \((2, 3, -4)\) and parallel to the vector \(6\,\hat i\, + 3\hat j\, - 4\hat k\) is
- A \(7\)
- B \(4\sqrt 3\)
- C \(2\sqrt {13}\)
- D \(6\)
Answer & Solution
Correct Answer
(A) \(7\)
Step-by-step Solution
Detailed explanation
\(AD = \left| {\frac{{\overrightarrow {AP} .\vec n}}{{\left| {\vec n} \right|}}} \right| = \sqrt {61} \) \(\Rightarrow P D=\sqrt{A P^{2}-A D^{2}}=\sqrt{110-61}=7\)
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