JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
Let \(X=\left[\begin{array}{lll}0 & 1 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 0\end{array}\right], Y=\alpha l+\beta X+\gamma X^{2} \quad\) and \(Z =\alpha^{2} I -\alpha \beta X +\left(\beta^{2}-\alpha \gamma\right) X ^{2}, \alpha, \beta, \gamma \in R\). If \(Y ^{-1}=\) \(\left[\begin{array}{ccc}\frac{1}{5} & \frac{-2}{5} & \frac{1}{5} \\ 0 & \frac{1}{5} & \frac{-2}{5} \\ 0 & 0 & \frac{1}{5}\end{array}\right]\), then \((\alpha-\beta+\gamma)^{2}\) is equal to
- A \(100\)
- B \(101\)
- C \(200\)
- D \(201\)
Answer & Solution
Correct Answer
(A) \(100\)
Step-by-step Solution
Detailed explanation
\(X =\left[\begin{array}{lll} 0 & 1 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 0 \end{array}\right], X ^{2}=\left[\begin{array}{lll} 0 & 0 & 1 \\ 0 & 0 & 0 \\ 0 & 0 & 0 \end{array}\right]\)…
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