JEE Mains · Maths · STD 12 - 8. Application and integration
The area enclosed by the curves \(y^2+4 x=4\) and \(y-2 x=2\) is :
- A \(\frac{25}{3}\)
- B \(\frac{22}{3}\)
- C \(9\)
- D \(\frac{23}{3}\)
Answer & Solution
Correct Answer
(C) \(9\)
Step-by-step Solution
Detailed explanation
\(y^2+4 x=4\) \(y^2=-4(x-1)\) \(A=\int \limits_{-4}^2\left(\frac{4-y^2}{4}-\frac{y-2}{2}\right) d y=9\)
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