JEE Mains · Maths · STD 11 - 9. straight line
Let \(L\) denote the line in the \(xy\)-plane with \(x\) and \(y\) intercepts as \(3\) and \(1\) respectively. Then the image of the point \((-1,-4)\) in this line is
- A \(\left(\frac{8}{5}, \frac{29}{5}\right)\)
- B \(\left(\frac{29}{5}, \frac{11}{5}\right)\)
- C \(\left(\frac{11}{5}, \frac{28}{5}\right)\)
- D \(\left(\frac{29}{5}, \frac{8}{5}\right)\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{11}{5}, \frac{28}{5}\right)\)
Step-by-step Solution
Detailed explanation
\(L: \frac{x}{3}+\frac{y}{1}=1 \Rightarrow x+3 y-3=0\) Image of point (-1,-4) \(\frac{x+1}{1}=\frac{y+4}{3}=-2\left(\frac{-1-12-3}{10}\right)\) \(\frac{x+1}{1}=\frac{y+4}{3}=\frac{16}{5}\) \(( x , y ) \equiv\left(\frac{11}{5}, \frac{28}{5}\right)\)
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