JEE Mains · Maths · STD 11 - 6. permutation and combination
The sum of all the \(4 -\) digit distinct numbers that can be formed with the digits \(1,2,2\) and \(3\) is
- A \(26664\)
- B \(122664\)
- C \(122234\)
- D \(22264\)
Answer & Solution
Correct Answer
(A) \(26664\)
Step-by-step Solution
Detailed explanation
Digits are \(1,2,2,3\) total distinct numbers \(\frac{4 !}{2 !}=12\). total numbers when \(1\) at unit place is \(3.\)3 \(2\) at unit place is \(6\) \(3\) at unit place is \(3 .\) So, sum \(=(3+12+9)\left(10^{3}+10^{2}+10+1\right)\) \(=(1111) \times 24\) \(=26664\)
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