JEE Mains · Maths · STD 11 - 9. straight line
Slope of a line passing through \(P(2, 3)\) and intersecting the line, \(x + y = 7\) at a distance of \(4\) units from \(P,\) is
- A \(\frac{{\sqrt 5 - 1}}{{\sqrt 5 + 1}}\)
- B \(\frac{{1 - \sqrt 5 }}{{1 + \sqrt 5 }}\)
- C \(\frac{{\sqrt 7 - 1}}{{\sqrt 7 + 1}}\)
- D \(\frac{{1 - \sqrt 7 }}{{1 + \sqrt 7 }}\)
Answer & Solution
Correct Answer
(D) \(\frac{{1 - \sqrt 7 }}{{1 + \sqrt 7 }}\)
Step-by-step Solution
Detailed explanation
\(x = 2 + r\,\cos \theta \) \(y = 3 + r\,\sin \theta \) \( \Rightarrow 2 + r\,\cos \theta + 3 + r\,\sin \theta = 7\) \( \Rightarrow r\left( {\cos \theta + \,\sin \theta } \right) = 2\)…
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