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JEE Mains · Maths · STD 12 - 13. probability

Bag \(I\) contains \(3\) red,\(4\) black and \(3\) white balls and Bag \(II\) contains \(2\) red,\(5\) black and \(2\) white balls. One ball is transferred from Bag \(I\) to Bag \(II\) and then a ball is draw from Bag \(II\). The ball so drawn is found to be black in colour. Then the probability, that the transferred ball is red,is.

  1. A \(\frac{4}{9}\)
  2. B \(\frac{5}{18}\)
  3. C \(\frac{1}{6}\)
  4. D \(\frac{3}{10}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{5}{18}\)

Step-by-step Solution

Detailed explanation

\(A :\) Drown ball from boy II is black \(B :\) Red ball transferred \(P\left(\frac{B}{A}\right)=\frac{P(A \cap B)}{P(A)}\) \(= \frac{3}{\frac{3}{9} \times \frac{5}{10}+\frac{4}{9} \times \frac{5}{10}+\frac{6}{9} \times \frac{5}{10}}\)…
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