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JEE Mains · Maths · STD 12 - 11. three dimension geometry

Let \((\lambda, 2,1)\) be a point on the plane which passes through the ponit \((4,-2,2) .\) If the plane is perpendicular to the line joining the points \((-2,-21,29)\) and \((-1,-16,23),\) then \(\left(\frac{\lambda}{11}\right)^{2}-\frac{4 \lambda}{11}-4\) is equal to

  1. A \(4\)
  2. B \(5\)
  3. C \(8\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(8\)

Step-by-step Solution

Detailed explanation

\(\overline{ AB } \cdot \overline{ PQ }=0\) \(\Rightarrow(\hat{ i }+5 \hat{ j }-6 \hat{ k }) \cdot((4-\lambda) \hat{ i }-4 \hat{ j }+\hat{ k })=0\) \(\Rightarrow 4-\lambda-20-6=0\) \(\Rightarrow \lambda=-22\)…
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