JEE Mains · Maths · STD 12 - 11. three dimension geometry
Let \((\lambda, 2,1)\) be a point on the plane which passes through the ponit \((4,-2,2) .\) If the plane is perpendicular to the line joining the points \((-2,-21,29)\) and \((-1,-16,23),\) then \(\left(\frac{\lambda}{11}\right)^{2}-\frac{4 \lambda}{11}-4\) is equal to
- A \(4\)
- B \(5\)
- C \(8\)
- D \(6\)
Answer & Solution
Correct Answer
(C) \(8\)
Step-by-step Solution
Detailed explanation
\(\overline{ AB } \cdot \overline{ PQ }=0\) \(\Rightarrow(\hat{ i }+5 \hat{ j }-6 \hat{ k }) \cdot((4-\lambda) \hat{ i }-4 \hat{ j }+\hat{ k })=0\) \(\Rightarrow 4-\lambda-20-6=0\) \(\Rightarrow \lambda=-22\)…
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