JEE Mains · Maths · STD 12 - 13. probability
Let \(X\) be a binomially distributed random variable with mean \(4\) and variance \(\frac{4}{3}\). Then \(54 P ( X \leq 2)\) is equal to.
- A \(\frac{73}{27}\)
- B \(\frac{146}{27}\)
- C \(\frac{146}{81}\)
- D \(\frac{126}{81}\)
Answer & Solution
Correct Answer
(B) \(\frac{146}{27}\)
Step-by-step Solution
Detailed explanation
\(np =4\) \(npq =4 / 3\) \(n =6, p =2 / 3, q =1 / 3\) \(54( P ( X =2)+ P ( X =1)+ P ( X =0))\)…
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