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JEE Mains · Maths · STD 12 - 10. vector algebra

Let \(x_{0}\) be the point of local maxima of \(f(x)=\vec{a} \cdot(\vec{b} \times \vec{c}),\) where \(\vec{a}=x \hat{i}-2 \hat{j}+3 \hat{k}\) \(\overrightarrow{ b }=-2 \hat{ i }+ x \hat{ j }-\hat{ k }\) and \(\overrightarrow{ c }=7 \hat{ i }-2 \hat{ j }+ x \hat{ k } \cdot\) Then the value of \(\vec{a} \cdot \vec{b}+\vec{b} \cdot \vec{c}+\vec{c} \cdot \vec{a}\) at \(x=x_{0}\) is 

  1. A \(-30\)
  2. B \(14\)
  3. C \(-4\)
  4. D \(-22\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(-22\)

Step-by-step Solution

Detailed explanation

\(f(x)=\vec{a} \cdot(\vec{b} \times \vec{c})=\left|\begin{array}{ccc}x & -2 & 3 \\ -2 & x & -1 \\ 7 & -2 & x\end{array}\right|=x^{3}-27 x+26\) \(f^{\prime}(x)=3 x^{2}-27=0 \Rightarrow x=\pm 3\) and \(f ^{\prime \prime}(-3)<0\) \(\Rightarrow\) local maxima at \(x=x_{0}=-3\) Thus,…