JEE Mains · Maths · STD 12 - 11. three dimension geometry
Let the line L pass through \((1,1,1)\) and intersect the lines \(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}\) and \(\frac{x-3}{1}=\frac{y-4}{2}=\frac{z}{1}\) . Then, which of the following points lies on the line L ?
- A \((4,22,7)\)
- B \((5,4,3)\)
- C \((10,-29,-50)\)
- D \((7,15,13)\)
Answer & Solution
Correct Answer
(D) \((7,15,13)\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Dr's of } \mathrm{AC} \Rightarrow 2 \lambda, 3 \lambda-2,4 \lambda \\ & \text { Dr's of } \mathrm{BC} \Rightarrow \mu+2,2 \mu+3, \mu-1 \\ & \Rightarrow \frac{\mu+2}{2 \lambda}=\frac{2 \mu+3}{3 \lambda-2}=\frac{\mu-1}{4 \lambda} \\ & \Rightarrow…
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