JEE Mains · Maths · STD 12 - 9. differential equations
Let the solution curve \(x=x(y), 0 < y < \frac{\pi}{2}\), of the differential equation \(\left(\log _e(\cos y)\right)^2 \cos y dx -(1+3 x\) \(\left.\log _e(\cos y)\right) \sin y dy =0\) satisfy \(x\left(\frac{\pi}{3}\right)=\frac{1}{2 \log _e 2}\). If \(x\left(\frac{\pi}{6}\right)=\frac{1}{\log _e m-\log _e n}\), where \(m\) and \(n\) are co-prime, then \(mn\) is equal to \(.....\).
- A \(12\)
- B \(11\)
- C \(10\)
- D \(13\)
Answer & Solution
Correct Answer
(A) \(12\)
Step-by-step Solution
Detailed explanation
\(\operatorname{Cos} y \ln ^2 \cos y d x=(1+3 x \ln \cos y) \sin y d y\) \(\frac{d x}{d y}=\tan y\left(\frac{3 x}{\ln \cos y}+\frac{1}{\ln ^2 \cos y}\right)\) \(\frac{d x}{d y}-\left(\frac{3 \tan y}{\ln \cos y}\right) x=\frac{\tan y}{\ln ^2 \cos y}\)…
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