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JEE Mains · Maths · STD 12 - 6. Application of derivatives

The sum of the absolute minimum and the absolute maximum values of the function \(f(x)=\left|3 x-x^{2}+2\right|-x\) in the interval \([-1,2]\) is

  1. A \(\frac{\sqrt{17}+3}{2}\)
  2. B \(\frac{\sqrt{17}+5}{2}\)
  3. C \(5\)
  4. D \(\frac{9-\sqrt{17}}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{\sqrt{17}+3}{2}\)

Step-by-step Solution

Detailed explanation

\(f(x)=\left\{\begin{array}{ll}x^{2}-4 x-2, & \forall x \in\left(-1, \frac{3-\sqrt{17}}{2}\right) \\ -x^{2}+2 x+2, & \forall x \in\left(\frac{3-\sqrt{17}}{2}, 2\right)\end{array}\right.\) \(f^{\prime}(x)\) when \(x \in\left(-1, \frac{3-\sqrt{17}}{2}\right)\)…