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JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
The tangent to the circle \(C_1 : x^2 + y^2 - 2x- 1\, = 0\) at the point \((2, 1)\) cuts off a chord of length \(4\) from a circle \(C_2\) whose centre is \((3, - 2)\). The radius of \(C_2\) is
- A \(\sqrt 6 \)
- B \(2\)
- C \(\sqrt 2 \)
- D \(3\)
Answer & Solution
Correct Answer
(A) \(\sqrt 6 \)
Step-by-step Solution
Detailed explanation
Here, equation of tangent on \({C_1}\) at \(\left( {2,1} \right)\) is: \(2x + y - \left( {x + 2} \right) - 1 = 0\) Or \(x + y = 3\) If it cuts off the chord of the circle \({C_2}\) then the equation of the chord is : \(x + y = 3\) \(\therefore \) distance of the chord from…
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