JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
Let the parabola \(y=x^2+\mathrm{p} x-3\), meet the coordinate axes at the points \(\mathrm{P}, \mathrm{Q}\) and R . If the circle C with centre at \((-1,-1)\) passes through the points \(P, Q\) and \(R\), then the area of \(\triangle P Q R\) is :
- A \(7\)
- B \(4\)
- C \(6\)
- D \(5\)
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
\(\mathrm{y}=\mathrm{x}^2+\mathrm{px}-3\) Let \(\mathrm{P}(\alpha, 0), \mathrm{Q}(\beta, 0), \mathrm{R}(0,-3)\) Circle with centre \((-1,-1)\) is \((x+1)^2+(y+1)^2=r^2\) Passes through \((0,-3)\) \(\begin{aligned} & \left.1^2+(-2)^2=r^2\right] \\ & \mathrm{r}^2=5 \end{aligned}\)…
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