JEE Mains · Maths · STD 11 - 6. permutation and combination
Let the number of elements in sets \(A\) and \(B\) be five and two respectively. Then the number of subsets of \(A \times B\) each having at least \(3\) and at most \(6\) element is :
- A \(792\)
- B \(752\)
- C \(782\)
- D \(772\)
Answer & Solution
Correct Answer
(A) \(792\)
Step-by-step Solution
Detailed explanation
\(n ( A \times B )=10\) \({ }^{10} C _3+{ }^{10} C _4+{ }^{10} C _5+{ }^{10} C _6=792\)
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