JEE Mains · Maths · STD 11 - 13. statistics
The variance of first \(50\) even natural numbers is
- A \(437\)
- B \(\frac{{437}}{4}\)
- C \(\frac{{833}}{4}\)
- D \(833\)
Answer & Solution
Correct Answer
(D) \(833\)
Step-by-step Solution
Detailed explanation
\(2,4,6,8,......,98,100\) \({\sigma ^2} = \frac{{\sum x_1^2}}{n} - {\left( {\overline {.x} } \right)^2}\) \(\frac{{{2^2} + {4^2} + {6^2} + .... + {{100}^2}}}{{50}}\)\( - {\left( {\frac{{2 + 4 + 6 + .... + 100}}{{50}}} \right)^2}\)…
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