JEE Mains · Maths · STD 11 - 14. probability
The probability, that in a randomly selected \(3-\)digit number at least two digits are odd, is
- A \(\frac{19}{36}\)
- B \(\frac{15}{36}\)
- C \(\frac{13}{36}\)
- D \(\frac{23}{36}\)
Answer & Solution
Correct Answer
(A) \(\frac{19}{36}\)
Step-by-step Solution
Detailed explanation
\(=\) exactly two digits are odd \(+\) exactly there 3 digits are odd For exactly three digits are odd For exactly two digits odd : If \(0\) is used then \(: 2 \times 5 \times 5=50\) If \(0\) is not used then : \({ }^{3} C _{1} \times 4 \times 5 \times 5=300\) Required…
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