JEE Mains · Maths · STD 12 - 11. three dimension geometry
Let the image of the point \(P (1,2,3)\) in the plane \(2 x\) \(-y+z=9\) be \(Q\). If the coordinates of the point \(R\) are \((6,10,7)\), then the square of the area of the triangle \(PQR\) is \(.....\).
- A \(591\)
- B \(592\)
- C \(593\)
- D \(594\)
Answer & Solution
Correct Answer
(D) \(594\)
Step-by-step Solution
Detailed explanation
Let \(Q \quad(\alpha, \beta, \gamma)\) be the image of \(P\), about the plane \(2 x-y+z=9\) \(\frac{\alpha-1}{2}=\frac{\beta-2}{-1}=\frac{\gamma-3}{1}=2\) \(\Rightarrow \alpha=5, \beta=0, \gamma=5\) Then area of triangle \(PQR\) is…
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