JEE Mains · Maths · STD 12 - 11. three dimension geometry
Let \(\mathrm{P}\) be a plane passing through the points \((2,1,0),(4,1,1)\) and \((5,0,1)\) and \(R\) be any point \((2,1,6) .\) Then the image of \(\mathrm{R}\) in the plane \(\mathrm{P}\) is
- A \((6,5,-2)\)
- B \((4,3,2)\)
- C \((3,4,-2)\)
- D \((6,5,2)\)
Answer & Solution
Correct Answer
(A) \((6,5,-2)\)
Step-by-step Solution
Detailed explanation
Let \(I\) and \(\mathrm{F}\) are respectively image and foot of perpendicular of point \(\mathrm{P}\) in the plane. \(\mathrm{eq}^{\mathrm{n}}\) of line \(\mathrm{PI} \frac{\mathrm{x}-2}{1}=\frac{\mathrm{y}-1}{1}=\frac{\mathrm{z}-6}{-2}=\lambda(\mathrm{say})\) Let…
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