JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations
The sum of the cubes of all the roots of the equation \(x^{4}-3 x^{3}-2 x^{2}+3 x+1=10\) is
- A \(34\)
- B \(36\)
- C \(44\)
- D \(46\)
Answer & Solution
Correct Answer
(B) \(36\)
Step-by-step Solution
Detailed explanation
\(x^{4}-3 x^{3}-2 x^{2}+3 x+1=10\) \(x=0\) is not the root of this equation so divide it by \(x^{2}\) \(x^{2}-3 x-2+\frac{3}{x}+\frac{1}{x^{2}}=0\) \(x^{2}+\frac{1}{x^{2}}-2+2-3\left(x-\frac{1}{x}\right)-2=0\) \(\left(x-\frac{1}{x}\right)^{2}-3\left(x-\frac{1}{x}\right)=0\)…
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