JEE Mains · Maths · STD 12 - 1. relation and function
Let \(N\) be the set of natural numbers and a relation \(R\) on \(N\) be defined by \(R=\left\{(x, y) \in N \times N: x^{3}-3 x^{2} y-x y^{2}+3 y^{3}=0\right\} .\) Then the relation \(R\) is:
- A reflexive and symmetric, but not transitive
- B reflexive but neither symmetric nor transitive
- C an equivalence relation
- D symmetric but neither reflexive nor transitive
Answer & Solution
Correct Answer
(B) reflexive but neither symmetric nor transitive
Step-by-step Solution
Detailed explanation
\(x^{3}-3 x^{2} y-x y^{2}+3 y^{3}=0\) \(\Rightarrow x(x-y)(x+y)-3 y(x-y)(x+y)=0\) \(\Rightarrow(x-3 y)(x-y)(x+y)=0\) Now, \(x=y \forall(x, y) \in N \times N\) so reflexive But not symmetric \& transitive See, \((3,1)\) satisfies but \((1,3)\) does not. Also…
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