JEE Mains · Maths · STD 11 - 9. straight line
Let \(L\) be the line passing through the point \(P( 1, 2)\) such that its intercepted segment between the co-ordinate axes is bisected at \(P\). If \(L_1\) is the line perpendicular to \(L\) and passing through the point \((-2 , 1),\) then the point of intersection of \(L\) and \(L_1\) is
- A \(\left( {\frac{4}{5},\frac{{12}}{5}} \right)\)
- B \(\left( {\frac{3}{5},\frac{{23}}{{10}}} \right)\)
- C \(\left( {\frac{11}{20},\frac{{29}}{{10}}} \right)\)
- D \(\left( {\frac{3}{10},\frac{{17}}{{5}}} \right)\)
Answer & Solution
Correct Answer
(A) \(\left( {\frac{4}{5},\frac{{12}}{5}} \right)\)
Step-by-step Solution
Detailed explanation
Equation of line \(L\) \(\frac{x}{2} + \frac{y}{4} = 1\) \(2x + y = 4\,\,\,\,\,\,\,\,\,\,.....\left( 1 \right)\) For line \(x - 2y = - 4\,\,\,\,\,.......\left( 2 \right)\) solving equation \((1)\) and \((2)\); we get point of intersection \(\left( {4/5,\frac{{12}}{5}} \right)\)
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