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JEE Mains · Maths · STD 11 - 12. limits

Let \(f(x)\) be a differentiable function at \(x=a\) with \(f^{\prime}(a)=2\) and \(f(a)=4\). Then \(\lim _{x \rightarrow a} \frac{x f(a)-a f(x)}{x-a}\) equals ...... .

  1. A \(2 a +4\)
  2. B \(4-2 a\)
  3. C \(2 a-4\)
  4. D \(a +4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4-2 a\)

Step-by-step Solution

Detailed explanation

\(f^{\prime}(a)=2, f(a)=4\) \(\lim _{x \rightarrow a} \frac{x f(a)-a f(x)}{x-a}\) \(\Rightarrow \lim _{x \rightarrow a} \frac{f(a)-a f^{\prime}(x)}{1} \quad\) (Lopitals rule) \(=f(a)-a f^{\prime}(a)\) \(=4-2 a\)