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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

Let \(L_1, L_2\) be the lines passing through the point \(\mathrm{P}(0,1)\) and touching the parabola \(9 x^2+12 x+18 y-14=0\). Let \(Q\) and \(R\) be the points on the lines \(\mathrm{L}_1\) and \(\mathrm{L}_2\) such that the \(\triangle \mathrm{PQR}\) is an isosceles triangle with base \(\mathrm{QR}\). If the slopes of the lines \(Q R\) are \(m_1\) and \(m_2\). then \(16\left(m_1^2+m_2^2\right)\) is equal to ..............

  1. A \(68\)
  2. B \(25\)
  3. C \(46\)
  4. D \(74\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(68\)

Step-by-step Solution

Detailed explanation

\( 9 x^2+12 x+4=-18(y-1) \) \( (3 x+2)^2=-18(y-1) \) \( \left(x+\frac{2}{3}\right)^2=-2(y-1)\) \( (0,1) \) \( y=m x+1 \) \( \left(x+\frac{2}{3}\right)^2=-2(y-1) \) \( (3 x+2)^2=-18 m x \) \( 9 x^2+(12+18 m) x+4=0 \) \( 4(6+9 m)^2=4(36) \) \( 6+9 m=6,-6 \) \( m=0, \frac{-4}{3}\)…