JEE Mains · Maths · STD 12 - 8. Application and integration
Let \(a\) and \(\mathrm{b}\) respectively be the points of local maximum and local minimum of the function \(f(x)=2 x^{3}-3 x^{2}-12 x .\) If \(A\) is the total area of the region bounded by \(\mathrm{y}=\mathrm{f}(\mathrm{x})\), the \(\mathrm{x}\)-axis and the lines \(x=a\) and \(x=b\), then \(4 A\) is equal to ..... .
- A \(124\)
- B \(630\)
- C \(114\)
- D \(74\)
Answer & Solution
Correct Answer
(C) \(114\)
Step-by-step Solution
Detailed explanation
\(f^{\prime}(x)=6 x^{2}-6 x-12=6(x-2)(x+1)\) \(\text { Point }=(2,-20)\, \& \,(-1,7)\) \(A=\int_{-1}^{0}\left(2 x^{3}-3 x^{2}-12 x\right)\, d x+\int_{0}^{2}\left(12 x+3 x^{2}-2 x^{3}\right)\, d x\)…
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