JEE Mains · Maths · STD 11 - 7. binomial theoram
Let \(K\) be the sum of the coefficients of the odd powers of \(x\) in the expansion of \((1+ x )^{99}\). Let a be the middle term in the expansion of \(\left(2+\frac{1}{\sqrt{2}}\right)^{200}\). If \(\frac{{ }^{200} C _{99} K }{ a }=\frac{2^{\ell} m }{ n }\), where \(m\) and \(n\) are odd numbers, then the ordered pair \((l, n )\) is equal to :
- A \((50,51)\)
- B \((51,99)\)
- C \((50,101)\)
- D \((51,101)\)
Answer & Solution
Correct Answer
(C) \((50,101)\)
Step-by-step Solution
Detailed explanation
In the expansion of \((1+ x )^{99}= C _0+ C _1 x + C _2 x ^2+\ldots+ C _{99} x ^{99}\) \(K = C _1+ C _3+\ldots . .+ C _{99}=2^{98}\) \(a\) Middle in the expansion of \(\left(2+\frac{1}{\sqrt{2}}\right)^{200}\)…
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