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JEE Mains · Maths · STD 11 - 7. binomial theoram

Let \(K\) be the sum of the coefficients of the odd powers of \(x\) in the expansion of \((1+ x )^{99}\). Let a be the middle term in the expansion of \(\left(2+\frac{1}{\sqrt{2}}\right)^{200}\). If \(\frac{{ }^{200} C _{99} K }{ a }=\frac{2^{\ell} m }{ n }\), where \(m\) and \(n\) are odd numbers, then the ordered pair \((l, n )\) is equal to :

  1. A \((50,51)\)
  2. B \((51,99)\)
  3. C \((50,101)\)
  4. D \((51,101)\)
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Answer & Solution

Correct Answer

(C) \((50,101)\)

Step-by-step Solution

Detailed explanation

In the expansion of \((1+ x )^{99}= C _0+ C _1 x + C _2 x ^2+\ldots+ C _{99} x ^{99}\) \(K = C _1+ C _3+\ldots . .+ C _{99}=2^{98}\) \(a\) Middle in the expansion of \(\left(2+\frac{1}{\sqrt{2}}\right)^{200}\)…
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