JEE Mains · Maths · STD 12 - 11. three dimension geometry
If the image of the point \(\mathrm{P}(1,0,3)\) in the line joining the points \(\mathrm{A}(4,7,1)\) and \(\mathrm{B}(3,5,3)\) is \(\mathrm{Q}(\alpha, \beta, \gamma)\), then \(\alpha+\beta+\gamma\) is equal to
- A \(\frac{47}{3}\)
- B \(\frac{46}{3}\)
- C \(18\)
- D \(13\)
Answer & Solution
Correct Answer
(B) \(\frac{46}{3}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{P}(1,0,3) \\ & \mathrm{A}(4,7,1), \mathrm{B}(3,5,3) \\ & \text { Line } \mathrm{AB} \Rightarrow \frac{\mathrm{x}-3}{1}=\frac{\mathrm{y}-5}{2}=\frac{\mathrm{z}-3}{-2}=\lambda \end{aligned}\) Let foot of perpendicular of P on AB be…
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