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JEE Mains · Maths · STD 11 - 8. sequence and series

If \(\alpha, \beta\) are natural numbers such that \(100^{\alpha}-199 \beta=(100)(100)+(99)(101)+(98)(102)\) \(+\ldots .+(1)(199),\) then the slope of the line passing through \((\alpha, \beta)\) and origin is

  1. A \(540\)
  2. B \(550\)
  3. C \(530\)
  4. D \(510\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(550\)

Step-by-step Solution

Detailed explanation

\(S =(100)(100)+(99)(101)+(98)(102) \ldots .\)\(\ldots(2)(198)+(1)(199)\) \(S =\sum_{ x =0}^{99}(100- x )(100+ x )=\sum 100^{2}- x ^{2}\) \(=100^{3}-\frac{99 \times 100 \times 199}{6}\) \(\alpha=3 \quad \beta=1650\) slope \(=\frac{1650}{3}=550\)