JEE Mains · Maths · STD 12 - 1. relation and function
Let \(f : R \rightarrow R\) be a function defined by \(f ( x )=\) \(\log _{\sqrt{m}}\{\sqrt{2}(\sin x-\cos x)+m-2\}\), for some \(m\), such that the range of \(f\) is \([0,2]\). Then the value of \(m\) is \(............\)
- A \(5\)
- B \(3\)
- C \(2\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
Since, \(-\sqrt{2} \leq \sin x-\cos x \leq \sqrt{2}\) \(\therefore-2 \leq \sqrt{2}(\sin x-\cos x) \leq 2\) \(\quad \text { Assume } \sqrt{2}(\sin x-\cos x)=k)\) \(-2 \leq k \leq 2 \quad \ldots( i )\) \(f(x)=\log _{\sqrt{m}}( k + m -2)\) \(\text { Given, }\)…
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