JEE Mains · Maths · STD 11 - 6. permutation and combination
The number of ways in which \(21\) identical apples can be distributed among three children such that each child gets at least \(2\) apples, is
- A \(406\)
- B \(130\)
- C \(142\)
- D \(136\)
Answer & Solution
Correct Answer
(D) \(136\)
Step-by-step Solution
Detailed explanation
After giving \(2\) apples to each child \(15\) apples left now \(15\) apples can be distributed in \({ }^{15+3-1} \mathrm{C}_2={ }^{17} \mathrm{C}_2\) ways \(=\frac{17 \times 16}{2}=136\)
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