JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
The straight line \(x + 2y = 1\) meets the coordinate axes at \(A\) and \(B\). A circle is drawn through \(A, B\) and the origin. Then the sum of perpendicular distances from \(A\) and \(B\) on the tangent to the circle at the origin is
- A \(\frac {\sqrt 5}{2}\)
- B \(2\sqrt 5\)
- C \(\frac {\sqrt 5}{4}\)
- D \(4\sqrt 5\)
Answer & Solution
Correct Answer
(A) \(\frac {\sqrt 5}{2}\)
Step-by-step Solution
Detailed explanation
Equation of circle \(x\left( {x - 1} \right) + \left( {y - \frac{1}{2}} \right)y = 0\) \({x^2} + {y^2} - x - \frac{y}{2} = 0\) Equation of tangent at \(\left( {0,0} \right)\) \(x.0 + y.0 - \frac{{x + 0}}{2} - \frac{{y + 0}}{{2 \times 2}} = 0\)…
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