JEE Mains · Maths · STD 12 - 13. probability
If a random variable \(X\) follows the Binomial distribution \(B (33, p )\) such that \(3 P ( X =0)= P ( X =1)\), then the value of \(\frac{ P ( X =15)}{ P ( X =18)}-\frac{ P ( X =16)}{ P ( X =17)}\) is equal to
- A \(1320\)
- B \(1088\)
- C \(\frac{120}{1331}\)
- D \(\frac{1088}{1089}\)
Answer & Solution
Correct Answer
(A) \(1320\)
Step-by-step Solution
Detailed explanation
\(n =33\), let probability of success is \(p\) and \(q =1- p\) \(3 p ( x =0)= p ( x =1)\) 3. \({ }^{33} C _{0}( q )^{33}={ }^{33} C _{1} pq ^{32}\) \(p =\frac{1}{12}, q =\frac{11}{12}, \frac{ q }{ p }=11\) \(\frac{ p ( x =15)}{ p ( x =18)}-\frac{ p ( x =16)}{ p ( x =17)}\)…
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