JEE Mains · Maths · STD 11 - 13. statistics
If the mean and variance of the data \(65,68,58,44\), \(48,45,60, \alpha, \beta, 60\) where \(\alpha>\beta\) are \(56\) and \(66.2\) respectively, then \(\alpha^2+\beta^2\) is equal to
- A \(6435\)
- B \(6798\)
- C \(6344\)
- D \(4312\)
Answer & Solution
Correct Answer
(C) \(6344\)
Step-by-step Solution
Detailed explanation
\( \overline{\mathrm{x}}=56 \) \( \sigma^2=66.2 \) \( \Rightarrow \frac{\alpha^2+\beta^2+25678}{10}-(56)^2=66.2 \) \( \therefore \alpha^2+\beta^2=6344\)
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