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JEE Mains · Maths · STD 12 - 12. linear programming

If the set of all solutions of \(|x^2 + x - 9| = |x| + |x^2 - 9|\) is \([\alpha, \beta] \cup [\gamma, \infty)\), then \((\alpha^2 + \beta^2 + \gamma^2)\) is equal to:

  1. A \(9\)
  2. B \(18\)
  3. C \(36\)
  4. D \(72\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(18\)

Step-by-step Solution

Detailed explanation

The given equation is \(|x^2 + x - 9| = |x| + |x^2 - 9|\). Let \(A = x\) and \(B = x^2 - 9\). Then \(A + B = x^2 + x - 9\). The equation is of the form \(|A + B| = |A| + |B|\), which holds true if and only if \(A \cdot B \ge 0\). Substituting the values of \(A\) and \(B\):…
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