JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
Let \(\frac{d y}{d x}=\frac{a x-b y+a}{b x+c y+a}\), where \(a , b , c\) are constants, represent a circle passing through the point \((2,5)\). Then the shortest distance of the point \((11,6)\) from this circle is
- A \(10\)
- B \(7\)
- C \(8\)
- D \(5\)
Answer & Solution
Correct Answer
(C) \(8\)
Step-by-step Solution
Detailed explanation
Let equation of circle is \(x ^{2}+ y ^{2}+2 gx +2 fy + c =0\) \(\Rightarrow \frac{d y}{d x}=\frac{-(2 x+2 g)}{(2 y+2 f)}\) \(\text { Comparing with } \frac{d y}{d x}=\frac{a x-b y+a}{b x+c y+a}\) \(\Rightarrow b =0, a =-2, c =2 \quad b\)…
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