JEE Mains · Maths · STD 12 - 5. continuity and differentiation
Let \(f ( x )=\min \{1,1+ x \sin x \}, 0 \leq x \leq 2 \pi\). If \(m\) is the number of points, where \(f\) is not differentiable and \(n\) is the number of points, where \(f\) is not continuous, then the ordered pair \(( m , n )\) is equal to
- A \((2,0)\)
- B \((1,0)\)
- C \((1,1)\)
- D \((2,1)\)
Answer & Solution
Correct Answer
(B) \((1,0)\)
Step-by-step Solution
Detailed explanation
No. of non-differentiable points \(=1\;( m )\) No. of not continuous points \(=0\;(n)\) \((m,n)=(1,0)\)
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