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JEE Mains · Maths · STD 11 - 8. sequence and series

If \(n\) be odd or even, then the sum of \(n\) terms of the series \(1 - 2 + \) \(3 - \)\(4 + 5 - 6 + ......\) will be

  1. A \( - \frac{n}{2}\)
  2. B \(\frac{{n - 1}}{2}\)
  3. C \(\frac{{n + 1}}{2}\)
  4. D (a) and (c) both
Verified Solution

Answer & Solution

Correct Answer

(D) (a) and (c) both

Step-by-step Solution

Detailed explanation

(d) Given series \(S = 1 - 2 + 3 - 4 + 5 - 6.........\) Case \(I\) : If \(n\) is odd, say \(2m + 1\) In this case, the number of positive terms \( = \frac{1}{2}(n + 1) = \frac{1}{2}(2m + 1 + 1) = (m + 1)\) and the number of negative terms \( = (2m + 1) - (m + 1) = m\) Then sum…
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