JEE Mains · Maths · STD 12 - 8. Application and integration
Let \(A = \left\{ {\left( {x,y} \right):{y^2} \le 4x,y - 2x \ge - 4} \right\}\) .The area of the region \(A\) is
- A \(8\)
- B \(9\)
- C \(10\)
- D \(11\)
Answer & Solution
Correct Answer
(B) \(9\)
Step-by-step Solution
Detailed explanation
\(=\left|\int_{2}^{4}\left(\frac{y+4}{2}\right) d y\right|-\int_{-2}^{4} \frac{y^{2}}{4} d y\) \( = \left. {\frac{1}{2}\left[ {\frac{{{y^2}}}{2} + 4y} \right]_{ - 2}^4} \right| - \left| {\frac{1}{4}\left[ {\frac{{{y^3}}}{3}} \right]_{ - 2}^4} \right.\)…
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