JEE Mains · Maths · STD 11 - 7. binomial theoram
Let \([t]\) denotes the greatest integer \(\leq t\). If the constant term in the expansion of \(\left(3 x^2-\frac{1}{2 x^5}\right)^7\) is \(\alpha\), then \([\alpha]\) is equal to \(............\).
- A \(1274\)
- B \(1275\)
- C \(1273\)
- D \(1272\)
Answer & Solution
Correct Answer
(B) \(1275\)
Step-by-step Solution
Detailed explanation
\(\left(3 x ^2-\frac{1}{2 x ^5}\right)^7\) \(T _{ r +1}={ }^7 C _{ r }\left(3 x ^2\right)^{7- r }\left(-\frac{1}{2 x ^5}\right)^{ r }\) \(14-2 r -5 r =14-7 r =0\) \(\therefore r =2\)…
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