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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

If \(y(x)=\left(x^{x^{x}}\right), x>0\) then \(\frac{d^{2} x}{d y^{2}}+20\) at \(x=1\) is equal to

  1. A \(06\)
  2. B \(16\)
  3. C \(26\)
  4. D \(36\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(16\)

Step-by-step Solution

Detailed explanation

\(y=(x)=\left(x^{x}\right)^{x}\) \(\ln y ( x )= x ^{2} \cdot \ln x\) \(\frac{1}{y(x)} \cdot y^{\prime}(x)=\frac{x^{2}}{x}+2 x \cdot \ln x\) \(y^{\prime}(x)=y(x)[x+2 x \ln x]\) \(y(1)=1 ; y^{\prime}(1)=1\)…
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