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JEE Mains · Maths · STD 12 - 10. vector algebra

Let : \(\overrightarrow{ a }=\hat{ i }+2 \hat{ j }+3 \hat{ k }, \overrightarrow{ b }=\hat{ i }-\hat{ j }+2 \hat{ k }\) and \(\vec{c}=5 \hat{i}-3 \hat{j}+3 \hat{k}\) be there vectors. If \(\vec{r}\) is a vector such that, \(\overrightarrow{ r } \times \overrightarrow{ b }=\overrightarrow{ c } \times \overrightarrow{ b }\) and \(\overrightarrow{ r } \cdot \overrightarrow{ a }=0\). Then \(25|\overrightarrow{ r }|^2\) is equal to

  1. A \(449\)
  2. B \(336\)
  3. C \(339\)
  4. D \(560\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(339\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow{ a }=\hat{ i }+2 \hat{ j }+3 \hat{ k }\) \(\overrightarrow{ b }=\hat{ i }-\hat{ j }+2 \hat{ k }\) \(\overrightarrow{ c }=\hat{5 i }-3 \hat{ j }+3 \hat{ k }\)…