JEE Mains · Maths · STD 11 - 14. probability
Let \(A\) denote the event that a \(6 -\)digit integer formed by \(0,1,2,3,4,5,6\) without repetitions, be divisible by \(3 .\) Then probability of event \(A\) is equal to :
- A \(\frac{9}{56}\)
- B \(\frac{4}{9}\)
- C \(\frac{3}{7}\)
- D \(\frac{11}{27}\)
Answer & Solution
Correct Answer
(B) \(\frac{4}{9}\)
Step-by-step Solution
Detailed explanation
Total cases : \(\underline{6} \cdot \underline{6} \cdot \underline{\underline{5}} \cdot \underline{4} \cdot \underline{3} \cdot \underline{2}\) \(n(s)=6 \cdot 6 !\) Favourable cases : Number divisible by \(3 \equiv\) Sum of digits must be divisible by 3 Case\(-I\)…
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