JEE Mains · Maths · STD 12 - 10. vector algebra
Let \(\vec{p}=2 \hat{i}+3 \hat{j}+k\) and \(\vec{q}=\hat{i}+2 \hat{j}+k\) be two vectors. If \(a\) vector \(\vec{r}=(a \hat{i}+\beta \hat{j}+\gamma k)\) is perpendicular to each of the vectors \((\vec{p}+\bar{q})\) and \((\vec{p}-\vec{q})\), and \(|\vec{r}|=\sqrt{3}\), then \(|\alpha|+|\beta|+|\gamma|\) is equal to \(.....\)
- A \(3\)
- B \(4\)
- C \(1\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(3\)
Step-by-step Solution
Detailed explanation
\(\overrightarrow{\mathrm{p}}=2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}+\hat{\mathrm{k}} \text { (Given) }\) \(\overrightarrow{\mathrm{q}}=\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\hat{\mathrm{k}}\) Now…
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