JEE Mains · Maths · STD 12 - 9. differential equations
Let a curve \(y=y(x)\) be given by the solution of the differential equation \(\cos \left(\frac{1}{2} \cos ^{-1}\left(e^{-x}\right)\right) d x=\sqrt{e^{2 x}-1} \,d y\) If it intersects \(y\)-axis at \(y=-1\), and the intersection point of the curve with \(x\)-axis is \((\alpha, 0)\) the \(\mathrm{e}^{\alpha}\) is equal to \(.....\)
- A \(1\)
- B \(2\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
\(\cos \left(\frac{1}{2} \cos ^{-1}\left(e^{-x}\right)\right) d x=\sqrt{e^{2 x}-1} \,d y\) \(\text { Put } \cos ^{-1}\left(e^{-x}\right)=\theta, \theta \in[0, \pi]\) \(\operatorname{Cos} \theta=e^{-x} \Rightarrow 2 \cos ^{2} \frac{\theta}{2}-1=e^{-x}\)…
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