JEE Mains · Maths · STD 12 - 6. Application of derivatives
The sum of the abosolute maximum and minimum values of the function \(f(x)=\left|x^2-5 x+6\right|-3 x+2\) in the interval \([-1,3]\) is equal to :
- A \(10\)
- B \(12\)
- C \(13\)
- D \(24\)
Answer & Solution
Correct Answer
(A) \(10\)
Step-by-step Solution
Detailed explanation
\(f(x)=\left|x^2-5 x+6\right|-3 x+2\) \(f(x)=\left\{\begin{array}{cc}x^2-8 x+8 & ; x \in[-1,2] \\ -x^2+2 x-4 & ; x \in[2,3]\end{array}\right.\)
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