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JEE Mains · Maths · STD 11 - 4.1 complex nubers

Let a complex number \(z ,| z | \neq 1\), satisfy \(\log _{\frac{1}{\sqrt{2}}}\left(\frac{| z |+11}{(| z |-1)^{2}}\right) \leq 2 .\) Then, the largest value of \(|z|\) is equal to ............

  1. A \(8\)
  2. B \(7\)
  3. C \(6\)
  4. D \(5\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(7\)

Step-by-step Solution

Detailed explanation

\(\log _{\frac{1}{\sqrt{2}}}\left(\frac{|z|+11}{(|z|-1)^{2}}\right) \leq 2\) \(\frac{|z|+11}{(|z|-1)^{2}} \geq \frac{1}{2}\) \(2|z|+22 \geq(|z|-1)^{2}\) \(2|z|+22 \geq|z|^{2}+1-2|z|\) \(|z|^{2}-4|z|-21 \leq 0\) \(\Rightarrow|z| \leq 7\) \(\therefore \quad\) Largest value of…
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