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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola

The length of the latus rectum and directrices of a hyperbola with eccentricity e are 9 and \(\mathrm{x}= \pm \frac{4}{\sqrt{3}}\), respectively. Let the line \(y-\sqrt{3} \mathrm{x}+\sqrt{3}=0\) touch this hyperbola at \(\left(\mathrm{x}_0, \mathrm{y}_0\right)\). If \(\mathrm{m}\) is the product of the focal distances of the point \(\left(\mathrm{x}_0, \mathrm{y}_0\right)\), then \(4 \mathrm{e}^2+\mathrm{m}\) is equal to ...........

  1. A \(72\)
  2. B \(61\)
  3. C \(42\)
  4. D \(13\)
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Answer & Solution

Correct Answer

(B) \(61\)

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Detailed explanation

Given \(\frac{2 \mathrm{~b}^2}{\mathrm{a}}=9\) and \(\frac{\mathrm{a}}{\mathrm{e}}= \pm \frac{4}{\sqrt{3}}\) equation of tangent \(y-\sqrt{3} x+\sqrt{3}=0\) by equation of tangent Let slope \(=\mathrm{S}=\sqrt{3}\) Constant \(=-\sqrt{3}\) By condition of tangency…
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